Kinematic of Linear Motion 3

Area under the graph = area of trapezium

The gradient of the graph

Rearrange the equation, we get

p

pFrom

 (1)

 (2)

Substitute (1) in (2)

p

By substituting eq. (1) into eq. (2) thus

(3)

 (4)

Multiply (3) & (4)

p